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Let $G$ be a finite group with neutral element $e$.

Which of the following properties of $G$ is not equivalent to $G$ being solvable?

$G$ has a normal series with abelian factors.

$G$ has a subnormal series with strict inclusions and factors that are cyclic of prime order.

$G$ has a derived series which terminates in the trivial group $\{e\}$.

$G$ has a subnormal series with abelian factors.

$G$ has a derived series which terminates in the trivial group $\{e\}$ and has factors that are cyclic of prime order.