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Points A $(0,0)$, B $(5,0)$, and C $(0,-4)$ are joined to form a right triangle.

What is $\sin \angle $ ACB?

$ {\cfrac { 5 }{ \sqrt { 41 } } } $

$ {\cfrac { -4 }{ \sqrt { 41 } } } $

$ {\cfrac { -5 }{ 4 }} $

$ {\cfrac { -4 }{ 5 } } $

$ {\cfrac { 5 }{ 3} } $