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Which of the following quadratic equations has $-2$ and $ \cfrac { 4 }{ 3 } $ as solutions?

$ 3{ x }^{ 2 }-2x-8=0 $

$ 3{ x }^{ 2 }+2x-8=0 $

$ 3{ x }^{ 2 }-6x-24=0 $

$ x^{ 2 }+2x-24=0 $

$ 4x^{ 2 }-11x+6=0 $