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If the position vector of a particle for $t>0$ given by $\vec{s}(t)=\langle 4\cos{t^2}, \ln{t} \rangle$. What is the acceration vector of the particle?

$\langle -8t\cos{t^2}, \cfrac{1}{t} \rangle$

$\langle -16t^2\cos{t^2}-8\sin{t^2}, -\cfrac{1}{t^2} \rangle$

$\langle -8\sin{t^2}, \cfrac{1}{t} \rangle$

$\langle -16t^2\cos{t^2}, -\cfrac{1}{t^2} \rangle$