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If the position vector function of a particle is given by $\vec{s}(t)=\langle 5\cos{2t},\sin^2{t} \rangle$.

What is the velocity vector function for the particle?

$\langle 10\sin{2t}, 2\sin{t} \rangle$

$\langle -10\sin{2t}, 2\sin{t} \rangle$

$\langle -5\sin{2t}, 2\sin{t}\cos{t} \rangle$

$\langle -10\sin{2t}, 2\sin{t}\cos{t} \rangle$