Upgrade subject to access all content

Find the antiderivative:

$$\int e^{\sqrt{x}}dx$$

$2\sqrt{x}e^{\sqrt{x}}+C$

$e^{\sqrt{x}}+C$

$2e^{\sqrt{x}}\left ( \sqrt{x}-1 \right )+C$

$\cfrac{1}{2^{\sqrt{x}}}e^{\sqrt{x}}+C$