AP® Calculus AB-BC

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Difficult

Finding Position Vector from Acceleration Functions

APCALC-S51JAL

A particle travels along a path described parametrically by:

${ a }_{ x }={ t }^{ 2 }$
${ a }_{ y }=\cos(2t+3)$

If the particle starts from rest and has a final $x=833.333$, what is the position of the particle at $t=10\text{s}$ in vector notation?

A

$\left<833.333 , 0.230\right> $

B

$\left<833.333 , -0.133 \right> $

C

$\left< 833.333, -0.820\right> $

D

$\left< 833.333, -0.242 \right> $