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If $h\left( x \right) =\ln { \left( 3{ x }^{ 2 } \right) } $, then $h^{ \prime \prime }\left( 2 \right) =$

$-1$

$-\cfrac { 1 }{ 2 } $

$\cfrac { 1 }{ 2 } $

$\ln { \left( 12 \right) } $