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If $\cfrac{dy}{dx} =\sqrt{y^3-1}$ then $\cfrac{d^2 y}{dx^2}$ is:

$3y^2$

$-\cfrac{3y^2}{2}$

$\cfrac{3y^2}{2\sqrt{y^3-1}}$

$\cfrac{3y^2}{2}$