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Find the antiderivative:

$$\int { { \left( { x }^{ 2 }+3 \right) }^{ 2 } } dx$$

$\frac{1}{3}(x^{2}+3)^{3}+C$

$\frac{1}{5}x^{5}+2x^{3}+9x+C$

$4x(x^{2}+3)+C$

$\cfrac { { \left( { x }^{ 2 }+3 \right) }^{ 3 } }{ 6x } +C$