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Solve the differential equation $y^{\prime \prime} =6x+2$ if $y^\prime ( 0 ) =5$ and $y( 1 ) =10.$

$y={ x }^{ 3 }+{ x }^{ 2 }+5x-3$

$y={ x }^{ 3 }+{ x }^{ 2 }+5x+3$

$y={ x }^{ 3 }+{ x }^{ 2 }+5x+10$

$y={ x }^{ 3 }+{ x }^{ 2 }+5x-10$