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Evaluate the following integral using tabular integration:

$$\int _{ 0 }^{ 1 }{ { 2x }^{ 2 }\cos { xdx } } $$

$2\sin { 1-4\cos { 1 } } $

$-2\sin { 1+4\cos { 1 } } $

$6\sin { 1+4\sin { 1 } } $

$6\sin { 1-4\sin { 1 } } $