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Find the equation of the line tangent to the parametric curve given:

$x( t ) ={ -t }^{ 2 }+4t+12$$y( t ) =\cfrac{1}{t+1}$

...when $t=-2$.

$y+1=-\cfrac{1}{8}x$

$y-1=-\cfrac{1}{8}x$

$y-1=\cfrac{1}{8}x$

$y+1=8x$