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Find the tangent line to the polar curve $r=2$ at the point when $\theta=\cfrac{\pi}{3}$.

$y=-\cfrac{\sqrt{3}}{3}x+\cfrac{4\sqrt{3}}{3}$

$y=0$

$y=\sqrt{3}$

$y=-\cfrac{\sqrt{3}}{3}x+\cfrac{2\sqrt{3}}{3}$