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# The Definite Integral: Position of an Object

APCALC-CP9XPG

An object is moving along a straight line with position $x(t)$ at time $t$.

If the object's initial position is $x(0)=5$ and the object's velocity is given by $v(t)=\sqrt [ 3 ]{ 2+{ t }^{ 2 } }$, what is the position of the object at time $t=4$?

A

$2.391$

B

$2.621$

C

$7.391$

D

$12.391$