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# Rotational Inertia of a DVD

APPHMC-XNJW89

The standard DVD shown above has an outer diameter of $0.120\text{ m}$ and its interior hole has a diameter of $0.0150\text{ m}$. It has a mass of $0.0160 \text { kg}$ that can be assumed to be uniformly distributed. The equation for the rotational inertia, $I$, of a disk around its center is $\frac{1}{2} MR^2$.

What is the rotational inertia $I$ of the DVD?

A

$1.90 \times {10}^{-5}\text{ kg} \cdot \text{m}^2$

B

$2.88 \times {10}^{-5}\text{ kg} \cdot \text{m}^2$

C

$2.93 \times {10}^{-5}\text{ kg} \cdot \text{m}^2$

D

$5.80 \times {10}^{-5}\text{ kg} \cdot \text{m}^2$

E

$11.5 \times {10}^{-5}\text{ kg} \cdot \text{m}^2$