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A fair coin is tossed $8$ times.

What is the probability that $5$ of the resulting tosses land on heads?

$\left(\cfrac{8!}{(5!)(3!)}\right) \times (0.5^3) \times (0.5^5)$

$\left(\cfrac{8!}{(5!)(3!)}\right) \times (0.5^3) \times(0.5^8)$

$0.5^3 \times 0.5^5$

$8 \times 0.5^3 \times 0.5^5$

$\left(\cfrac{8!}{5!}\right) \times (0.5^3) \times (0.5^8)$