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# A Simple Exact Equation

DIFFEQ-CILTQ1

The solution curves for the equation $e^x+y^2+2xyy'=0$ are given by:

A

$e^x+2xy^2=C$

B

$y=\sqrt{(C-e^x)/x}$

C

$y=\sqrt{(C-2xy^2)/x}$

D

$e^x+xy^2=C$