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# Inverse Laplace Transform 14

DIFFEQ-ELFF18

Use the Laplace transform table to find the inverse Laplace transform of:

$$\frac{2s^2-s}{(s+1)(s-1)^2}$$

A

$\displaystyle (5/4) e^{-t} + (3/4) e^t + t e^{t}$

B

$\displaystyle (3/4) e^{-t} - (5/4) e^t - (1/2) t e^{t}$

C

$\displaystyle (5/4) e^{-t} + (3/4) e^t - t e^{t}$

D

$\displaystyle (3/4) e^{-t} + (5/4) e^t + (1/2) t e^{t}$