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# Solution to Initial Value Problem

DIFFEQ-I29XG4

Find the solution to the following initial value problem:

$$\begin{eqnarray*}u_1'&=&4u_1-3u_2,\ u_1(0)=1\\\ \\\ u_2'&=&6u_1-5u_2,\ u_2(0)=-1\end{eqnarray*}$$

A

$u_1(t)=e^{-2t}-e^t$, $u_2(t)=2e^{-2t}-e^t$

B

$u_1(t)=-2e^{-2t}+3e^t$, $u_2(t)=-4e^{-2t}+3e^t$

C

$u_1(t)=e^{-2t}$, $u_2(t)=-e^t$

D

$u_1(t)=-2e^t+3e^{-t}$, $u_2(t)=-4e^t+3e^{-t}$