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# Vector Force Calculation with Coulomb's Law

EANDM-NL9B3S

A charge $q_1 = 6.00 \: \mu \rm C$ is located at $\vec r_1 = (3.20 \widehat x + 4.70 \widehat y -9.00 \widehat z) \: \rm m$ and a second charge $q_2 = -3.00 \: \mu \rm C$ is located at $\vec r_2 = (7.00 \widehat x -9.20 \widehat y +15.0 \widehat z) \: \rm m$.

Determine the force in vector components that $q_1$ exerts on $q_2$.

A

$(6.62 \widehat x -27.3 \widehat z) \times 10^{-5} \:\rm N$

B

$(-28.0 \widehat x + 103 \widehat y -178 \widehat z) \:\rm N$

C

$(-5.6 \widehat x + 4.2 \widehat y -21.0 \widehat z) \times 10^{-5} \:\rm N$

D

$(-2.80 \widehat x + 10.3 \widehat y -17.8 \widehat z) \times 10^{-5} \:\rm N$

E

$(2.80 \widehat x - 10.3 \widehat y +17.8 \widehat z) \times 10^{-5} \:\rm N$