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Determining the Limiting Reactant: Excess Reactant

CHEM-1WHCUN

Given below is a balanced equation for the production of ammonia from nitrogen and hydrogen.

Determine the limiting reactant and the number of excess molecules for the reactant in excess when 76 molecules of $N_{2}$ react with 216 molecules of $H_{2}$.

$$N_{2}\ +\ 3H_{2}\rightarrow 2NH_{3}$$

$$\text{Nitrogen + hydrogen} \rightarrow \text{Ammonia}$$

A

$N_{2}$ is the limiting reactant and there will be 140 excess molecules of $H_{2}$.

B

$N_{2}$ is the limiting reactant and there will be 2 excess molecules of $H_{2}$.

C

$H_{2}$ is the limiting reactant and there will be 140 excess molecules of $N_{2}$.

D

$H_{2}$ is the limiting reactant and there will be 4 excess molecules of $N_{2}$.