General Chemistry

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Finding Empirical and Molecular Formula from Percent Composition


Combustion analysis of a hydrocarbon reveals that the hydrocarbon contains 85.63% C and 14.37% H.

Determine the ratio of C:H using the subscripts (x and y) in the empirical formula: $C_{x}H_{y}$.

Mass spectrometry found the molecular mass of the unknown hydrocarbon to be 56.11 amu.

Determine the ratio of C:H using subscripts (s and t) in the molecular formula: $C_{s}H_{t}$.