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General Chemistry

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Moderate

Limiting Reagent Problem: Using Molarity

CHEM-KWLYSI

How many grams of chromium (III) sulfate (MM = 392.18 g/mol) will be produced from the reaction of 50.0 mL of 0.225 M sodium sulfate (MM = 142.04 g/mol) with 30.0 mL of 0.350 M chromium (III) perchlorate (MM = 350.34 g/mol) via the following reaction?

$${ 3\ { Na }_{ 2 }{ SO }_{ 4 }\ \left( aq \right) \ +\ 2\ Cr{ \left( { ClO }_{ 4 } \right) }_{ 3 }\ (aq)\ \rightarrow { Cr }_{ 2 } }{ \left( { SO }_{ 4 } \right) }_{ 3 }\ \left( s \right) \ +\ 6\ { NaClO }_{ 4 }\ (aq)$$

A

4.41 g

B

4.12 g

C

2.06 g

D

1.47 g