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A given right triangle has the area $ \cfrac{8}{\sqrt3} $.

If this triangle has an angle of $30$ degrees, what is the new area of the triangle if the length of the shortest side is doubled?

$8$

$8\sqrt{3}$

$4\sqrt{3}$

$ \cfrac{64}{\sqrt3} $

$ \cfrac{32}{\sqrt3} $