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Linear Algebra

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Dimension of Subspace of $\mathbb{R}^5$

LINALG-NNEEBY

If:

$$W=\left\{\begin{pmatrix} x_1 \\\ x_2 \\\ x_3\\\ x_4\\\ x_5\end{pmatrix}\in\mathbb{R}^5\ \biggr|\ \ x_1+x_2+x_3=0\ ,\ x_4+x_5=0\right\}$$

...then $dim(W)$ equals:

A

$1$

B

$2$

C

$3$

D

$4$