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Write the below equation of Cartesian coordinates:

$$2x^2+2y^2+z^2=1$$

...in terms of cylindrical coordinates $(r,\theta,z).$

$2r^2+z^2=1$

$r^2+2z^2=4$

$r^2+2z^2=1$

$r^2-2z^2=4$

$2r^2-z^2=1$