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# Find the Distance of a Point from a Line

MVCALC-6LMKVU

The distance between the point $Q=(1,-1,3)$ and the line $L$ given by the symmetric equations:

$$\frac{x-2}{3}=\frac{y-4}{2}=\frac{z+1}{4}$$

...is of the form:

$$\frac{\sqrt{H}}{\sqrt{29}}$$

What is $H$?