Use the following equation to answer the relationship analysis question that follows.
$CaCl_2(aq) + Na_2CO_3(aq) → CaCO_3(s) + 2NaCl(aq)$
I. 2.50 g of $CaCl_2$ is fully dissolved in a beaker of water and 2.50 g of $Na_2CO_3$ is fully dissolved in water in a second beaker. The two solutions are mixed to form a $CaCO_3$ precipitate and aqueous $NaCl$. $Na_2CO_3$ will be the limiting reactant in this experiment.
II. Sodium carbonate has a molar mass which is less than the molar mass of calcium chloride.