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If the endpoints of the diameter of a circle are $(3, 7)$ and $(-1, -3)$, then which one of the following is the equation of the circle?

$(x-1)^{2}+(y-2)^{2}=29$

$(x-1)^{2}+(y-2)^{2}=841$

$(x+1)^{2}+(y+2)^{2}=29$

$(x-1)^{2}+(y-2)^{2}=116$

$(x+1)^{2}+(y+2)^{2}=116$