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# Half Angle Sine for 11.25 Degrees

TRIG-TKGZH5

Find the exact value for sine of $11.25^\circ$ using the half angle formula.​

A

$=\cfrac{\sqrt{2-\sqrt{2-\sqrt2}}}{4}$

B

$=\cfrac{\sqrt{2-\sqrt{2+\sqrt2}}}{2}$

C

$=\cfrac{\sqrt{2-\sqrt{2-\sqrt2}}}{2}$

D

$=\cfrac{\sqrt{2-\sqrt{2-\sqrt{2-\sqrt2}}}}{2}$

E

$=\cfrac{\sqrt{{\sqrt2}-1}}{2}$