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If $ 6x+8y=16 $, then:

$$ { (6x+8y) }^{ -\frac { 1 }{ 2 } }=? $$

A

$ -4 $

B

$ -8 $

C

$ \cfrac { 1 }{ 4 } $

D

$ \cfrac { 1 }{ 8 } $

E

$ -\cfrac { 1 }{ 4 } $

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