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Where does the line $y = 2x + 2$ intersect the circle:

$$ { x }^{ 2 }+{ y }^{ 2 }=8 $$

...where the solution is in the form $(x,y)$?

A

$\text{(-2,-2) only}$

B

$\text{(-2,-2) and }(\cfrac{2}{5}, \cfrac{14}{5}) \text {only }$

C

$\text{(-2,-2) and (-2,2) only}$

D

$(-2,2), (-2,-2), (\cfrac{2}{5}, \cfrac{14}{5}), \text{ and } (\cfrac{2}{5}, \cfrac{-14}{5})$

E

$\text{(2,2) and (-2,-2) only}$

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