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Where do the lines $4x - 3y = 0$ and $3x - (\frac{1}{4})y = 4$ intersect?

A

$(3, -4)$

B

$(\cfrac{3}{2}, 2)$

C

$(6, 8)$

D

$(-6, -8)$

E

$(\cfrac{2}{3}, -2)$

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