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Solve:

$$e^{6+\ln(x)}=x-1$$

A

$x=\cfrac{-1}{e^6-1}$

B

$x=\cfrac{-1}{5}$

C

$x=\cfrac{-1}{e^7-1}$

D

$x=\cfrac{-1}{e^5-1}$

E

Cannot be solved

F

None of these

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