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If $f''\left( x \right) ={ x }^{ 3 }-3x$ and $f'\left( 1 \right) =0$, then $f'\left( x \right)=$

A

$3{ x }^{ 2 }-3$

B

${ x }^{ 4 }-3{ x }^{ 2 }+2$

C

${ \cfrac { 1 }{ 4 } { x }^{ 4 } }-\cfrac { 3 }{ 2 } { x }^{ 2 }+1$

D

${ \cfrac { 1 }{ 4 } { x }^{ 4 } }-\cfrac { 3 }{ 2 } { x }^{ 2 }+\cfrac { 5 }{ 4 } $

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