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Find $\cfrac{dy}{dx}$ when $y=\cfrac{x^4-6x+12}{\sqrt{x}}$.

A

$\cfrac{dy}{dx}=\cfrac{7x^2 \sqrt{x}}{2}+\cfrac{3}{\sqrt{x}}+\cfrac{6}{x \sqrt{x}}$

B

$\cfrac{dy}{dx}=\cfrac{7x^2 \sqrt{x}}{2}-\cfrac{3}{\sqrt{x}}-\cfrac{6}{x \sqrt{x}}$

C

$\cfrac{dy}{dx}=2x^3 \sqrt{x}-3\sqrt{x}$

D

$\cfrac{dy}{dx}=\cfrac{4x^3}{\sqrt{x}}-\cfrac{6}{\sqrt{x}}$

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