Limited access

Upgrade to access all content for this subject

If $f(3)=-2$, $f'(3)=-8$, and $g(x)$ is the inverse function to $f(x)$, the equation of the tangent line to $g(x)$ at $x=-2$ is:

A

$y=-\cfrac{1}{8} (x+2)+3$

B

$y=\cfrac{1}{8} (x+2)+3$

C

$y=8(x-3)-2$

D

$y=-8(x-3)-2$

Select an assignment template