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A particle moves along the $x$-axis with a velocity $v( t ) ={ -t }^{ 2 }+6t-5.$

If $x = -2$ when $t = 0$, find the position of the particle when it is the farthest to the right.

A

$ -2$

B

$-\cfrac{1}{3}$

C

$\cfrac{19}{3}$

D

$\cfrac{25}{3}$

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