Limited access

Upgrade to access all content for this subject

Given the velocity vector $(2t-1, {2t }^{ 2 }-5t+2)$ determine the position of the particle when it is at rest if at time $t = 0$, its position is $(0, 0)$.

A

$ (0, 0)$

B

$ \left(-\dfrac{1}{4}, \dfrac{11}{24}\right)$

C

$ (-1, 2)$

D

$ \left(6, -\dfrac{2}{3}\right)$

Select an assignment template