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The surface area of a cube is increasing at a rate of $10\ \dfrac {\text{cm}^2}{\text{sec}}$.

How fast is the volume of the cube increasing when each edge of the cube is $5 \text{ cm}$?

$750\, \cfrac {\text{cm}^3} {\text{sec}}$

$75\, \cfrac {\text{cm}^3}{\text{sec}}$

$\cfrac{125}{2}\, \cfrac {\text{cm}^3}{\text{sec}}$

$\cfrac{25}{2}\, \cfrac {\text{cm}^3}{\text{sec}}$