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If DeMorgan's Law is used to negate the expression (i < j) && (k == m) then the result is:

A

(i > j) || (k != m)

B

(i < j) || (k == m)

C

(i > j) && (k != m)

D

(i >= j) && (k != m)

E

(i >= j) || (k != m)

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