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Three students have the task of designing a circuit that will store the maximum amount of electrical energy. The circuit contains a $12\text{ volt}$ source and two capacitors ($470\ \mu\text{F}$ and $330\ \mu\text{F}$) that are connected in series with the battery.

Student 1 insists that the present arrangement will store the most energy.

Student 2 thinks that the two capacitors should be arranged in parallel to store the most energy.

Student 3 argues that the $330\ \mu\text{F}$ capacitor should be removed and that the $470\ \mu\text{F}$ capacitor alone will store the most energy.

Which of the following explanations indicate which student is correct and why?

A

Student 1 is correct because capacitors connecting capacitors in series always ensures the charge on each capacitor is the same and a maximum.

B

Student 2 is correct because each capacitor will have the same maximum voltage, the battery voltage.

C

Student 3 is correct because anytime you add a smaller capacitor to a larger capacitor the equivalent capacitance is lower than either individual capacitor.

D

The best way to maximize the electrical energy is to remove the $470\ \mu\text{F}$ capacitor because the energy and capacitance have an inverse relationship.

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