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You, $\text{mass} = m$, are traveling at a constant velocity, $v$, on a skateboard. Your friend, $\text{mass} = 1.25m$, hops on and pushes off the ground with force, $F$, propelling the skateboard forward at a greater velocity. For simplicity, consider the skateboard is massless.

If the force is applied for a distance $d$, by which of the following factors did the kinetic energy change?


$1.25m{ v }^{ 2 }$


$\dfrac { 2Fd+m{ v }^{ 2 } }{ 2.25m } $


$\dfrac { 2Fd }{ m{v}^{2} } +1$



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