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You have two boxes on a frictionless surface.

Box A has twice the mass of Box B. You push left to right on the boxes with an applied force F.

In the first trial, the larger box is on the left and the smaller box is on the right.

Created for Albert.io. Copyright 2016. All rights reserved.

In the second trial, the smaller box is on the left and the larger box is on the right.

Created for Albert.io. Copyright 2016. All rights reserved.

Which of the following statements correctly compares the magnitude of the force exerted by Box A on Box B in the second trial to the magnitude of the force exerted by Box A on Box B in the first trial?

A

The force by Box A on Box B is the same in both trials because the applied force does not change.

B

The force by Box A on Box B is one third the force in the second trial because the smaller box is doing the pushing. The acceleration is one third of the force divided by the mass of the smaller box.

C

The force by Box A on Box B is twice as much for the second trial because the Box B must push a box with twice the mass.

D

The force by Box A on Box B is half as much for the second trial because Box B has only half the mass of Box A.

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