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The position of a particle as a function of time is given by $x(t) = ln (2 t + 3)$ for all positive $t$, where $x$ is in meters and $t$ is in seconds.

What is the particle's acceleration at $t = 10 sec$?

$-\frac {1} {23} m/s^{2}$

$-\frac {2} {23} m/s^{2}$

$-\frac {4} {529} m/s^{2}$

$-\frac {4} {23} m/s^{2}$

$-\frac {1} {5} m/s^{2}$