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The position varies with time for a particle undergoing simple harmonic motion given by:

$$x(t) = 2\sin(4t-6)$$

What is the acceleration of the particle as a function of time?

$a(t)=8\sin(4t-6)$

$a(t)=8\cos(4t-6)$

$a(t)=-16\sin(4t-6)$

$a(t)=-16\cos(4t-6)$

$a(t)=-32\sin(4t-6)$