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The position varies with time for a particle undergoing simple harmonic motion given by $x(t) = 2\sin(4t-6)$.

What is the acceleration of the particle as a function of time?

$8\cos(4t-6)$

$-16\cos(4t-6)$

$-16\sin(4t-6)$

$8\sin(4t-6)$

$-32\sin(4t-6)$