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Nick Borowicz. Created for Copyright 2016. All rights reserved.

A $2\text{ kg}$ mass is placed with its center of mass at $x= -10 \text{ cm}$ to the left of the fulcrum on a balance beam, as shown above. Two identical masses $m$ are placed with their centers of mass at $x=40\text{ cm}$ and $x=70\text{ cm}$ to the right of the fulcrum. The mass of the balance beam is negligible.

What must be the value of $m$ in order for the system to be in rotational equilibrium?


$0.02\text{ kg}$


$0.2 \text{ kg}$


$0.5\text{ kg}$


$1\text{ kg}$


$2\text{ kg}$

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