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A fair coin is tossed $8\text{ times}$.

What is the probability that $5$ of the resulting tosses land on heads?

$\left(\dfrac{8!}{(5!)(3!)}\right) \cdot (0.5^3) \cdot (0.5^5)$

$\left(\dfrac{8!}{(5!)(3!)}\right) \cdot (0.5^3) \cdot (0.5^8)$

$0.5^3 \cdot 0.5^5$

$8 \cdot 0.5^3 \cdot 0.5^5$

$\left(\dfrac{8!}{5!}\right) \cdot (0.5^3) \cdot (0.5^8)$